Math Chapter one

1)      AUB
U = Union mean write in sequence which also include repeat one time.
Let’s Example two set one is A and another one is B:

A =  {1, 2,  5,  8}    B = {  1, 3, 5, 9 }

AUB = A Union B

Answer.

   AUB = { 1,  2,   5,  8 }  U   { 1,  3,  5,  9}
   AUB ={1, 2, 3, 5, 8, 9}  Ans.

Note : which show the indicate of different color actualy write one this indicate means.

2)      A П B
П = intersection
Means write dupilcte value two set one time.

A =  {1, 2,  5,  8}    B = {  1, 3, 5, 9 }

A П B

AUB = A intersection  B

Answer.

   A П B  = { 1,  2,   5,  8 }  U   { 1,  3,  5,  9}
   AUB ={ 1 , 5 }  Ans.

Difference Between Two Set ( A – B)

           (A – B)
         ( --) show difference between two set
    We have sample difference number it like same.
Let’s example :
 (A-B) 
 A =  {1, 2,  5,  8}    B = {  1, 3, 5, 9 }
Answer.

   A - B = { 1,  2,   5,  8 } -  { 1,  3,  5,  9}
   AUB ={ 2 ,  8 }  Ans.

Write only A  set remaining value.

3)      ( A U B) П ( A U C)

A = {a, ,b c }  B = { b, c, d, e }  C= { c, d, e, f, h }

Taking Left Hand Side First

( A U B)

( A U B ) =  { a, b, c }  U {  b, c, d, e}
(AUB) = { a,b, c, d, e}

Taking right side
(A U C)

(A U C) = { a,b, c} U { b, c, d, e}

(A U C) = {a,b,c, d , e}

( A U B) П ( A U C)  Taking 

( A U B) П ( A U C) = {  a,b, c, d, e  } П {a,b,c, d , e}

( A U B) П ( A U C) =  {  a,b, c, d, e } Ans.


              Example De Morgan’s  Law

(AUB)’ = A’ПB’

( ‘ ) show Universal number

Let’s  U {  1, 2, 3, 4, 5, 6, 7 }, A= { 1, 3 5, 7}  B = { 3,4, 5, 6}

Solutions:

i)                    Here  U = {  1,  2, 3, 4, 5 , 6 , 7  }, A = { 1, 3, 5 ,7} and  B=  { 3, 4, 5, 6 }
          
First Taking Right Hand Side
AUB = {  1, 3, 5, 7, } U { 3, 4,  5, 6}

AUB = {  1,3,4,5,6,7 }


We find now,
(AUB)’ =  U – (AUB)

U – (AUB) =  ( 1, 2, 3, 4, 5, 6, 7 ) –  ( 1, 3, 4, 5, 6, 7 )

(AUB)’ =  {  2 }  because difference both set.

U – ( AUB) =  {  2  }      =>   

Taking Left Hand Side :

A’ПB’   = >   U – A   =>  U -B

  U – A = { 2,4, 6  }


A’  = >  U – A  =   { 1, 2, 3, 4, 5, 6, 7 } – { 1,  3, 5, 7 }   = > 


U- B =  { 1, 2, 7  }

B’  = >  U – B =  { 1, 2, 3, 4, 5, 6, 7   }  -  {  3, 4, 5, 6 }  =>    



A’П B’ =  {   2  } Ans.

A’ПB’    =  { 2,4, 6  }  П  { 1, 2, 7  }    = >


(AUB)’ = A’ПB’


Now you see that both value become same this means that we verify De – Morgam Rule.  

1 comment:

  1. Berlitz is Pakistan #1 English Language Learning Institute for Kids, Teens, Children and Adults.
    English Language for kids and Teens
    Special Summer Camp for kids and Teens in Karachi Islamabad and Lahore.
    Learning with Fun activities for kids and teens.
    Summer camp for kids and Teens
    Click to visit Website

    ReplyDelete